x^2+60x-1350=0

Solution for x^2+60x-1350=0 equation:

x^2+60x-1350=0

a = 1; b = 60; c = -1350;
Δ = b2-4ac
Δ = 602-4·1·(-1350)
Δ = 9000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9000}=\sqrt{900*10}=\sqrt{900}*\sqrt{10}=30\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-30\sqrt{10}}{2*1}=\frac{-60-30\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+30\sqrt{10}}{2*1}=\frac{-60+30\sqrt{10}}{2}
$